Scratch

JJROCKER wrote:

cpumaster930 wrote:

JJROCKER wrote:

I'm taking Physics this year also.

How about...

Reduce the Fraction: 4x(x+2)^2-2x^2(x+2)/(x+2)^3

That's a little confusing to be written on one line...do you think you could go into MS Paint or something like that, neatly draw out the equation as it appears on whatever worksheet the problem is from, upload the image to imgur or tinypic, and post it here?  Then I'd be able to understand it 

How about I make a scratch project?

That would work 

Is this correct?  I'd just like to confirm that before I start explaining it 

cpumaster930 wrote:

http://www4c.wolframalpha.com/Calculate … 2&h=44

Is this correct?  I'd just like to confirm that before I start explaining it 

I have another question so I'll make a project for it.

Ok, here goes. 


First, you can cancel one (x+2) from the bottom term and one (x+2) from each of the top terms, resulting in:


Second, you could separate into two terms, like this:


Cancel out one (x+2) from the top and bottom of the first term to get


I don't see anything else you can cancel there, although WolframAlpha insists that the result is

That was quite a tricky one...maybe there's something that I missed?

cpumaster930 wrote:

Ok, here goes. 
http://www4c.wolframalpha.com/Calculate … 2&h=44

First, you can cancel one (x+2) from the bottom term and one (x+2) from each of the top terms, resulting in:
http://www2.wolframalpha.com/Calculate/ … 1&h=43

Second, you could separate into two terms, like this:
http://www4d.wolframalpha.com/Calculate … 8&h=43

Cancel out one (x+2) from the top and bottom of the first term to get
http://www4d.wolframalpha.com/Calculate … 6&h=43

I don't see anything else you can cancel there, although WolframAlpha insists that the result is
http://www4d.wolframalpha.com/Calculate … 8&h=40
That was quite a tricky one...maybe there's something that I missed?

Mine says the answer is 2x(x^2+4)
                                          (x+2)^2

cpumaster930 wrote:

JJROCKER wrote:

and http://scratch.mit.edu/projects/JJROCKER/2016032

So that would be http://www2.wolframalpha.com/Calculate/ … 3&h=23, given that x^1/2 is the square root of x and y^1/4 is the fourth root of y.

The 100 and 81 coefficients look like the difference of two squares.  What makes this problem a bit harder than (10x+9y)(10x-9y) are the exponents.
If you take a half of 1/2, because you add exponents when you multiply, you get 10x^1/4, and taking half of 1/4, you get 9y^1/8.

WolframAlpha doesn't want to put it into fractional exponent notation, but here:
http://www4c.wolframalpha.com/Calculate … &h=32p

In text, though, it's
(10x^1/4+9y^1/8)(10x^1/4-9y^1/8)
I checked that result with W|A and it's correct ;D

And thanks, demosthenes, for that link--I'll be sure to check it out soon 

ok thanks! I get it! Awesome. Also, what is the thing demosthenes linked to?

..Adventure?

Isn't it just 1/(3x^2)? That was easy. Now find the derivative!

parcheesidude wrote:

randomnumber53 wrote:

Isn't it just 1/(3x^2)? That was easy. Now find the derivative!

-(1/6)x^(-3)

btw im 11

Whatever-- I'm bad at vocabulary. Plus I haven't done that stuff for 3 YEARS and I'm 14, so, we're even