X=X+1. How can a number equal itself plus 1? Would this be the formula for infinity?
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It's simply extraneous, or has an imaginary answer.
Last edited by Kileymeister (2010-12-19 21:25:38)
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find X and add 1 to it
yeah if X isn't any particular number, then this equation makes no sense.
I just won the award for Colonel Obvious
Last edited by militarydudes (2010-12-19 21:08:02)
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militarydudes wrote:
find X and add 1 to it
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yeah if you don't know what X is, then this equation makes no sense.
The purpose of the equation is to find X.
Like:
x-3=5
+3 +3
x=8
Last edited by Kileymeister (2010-12-19 21:07:56)
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midnightleopard wrote:
X=X+1. How can a number equal itself plus 1? Would this be the formula for infinity?
well if youre solving equations to see if its possible
x=x+1
-x=-x
0=1
and therefore the equation is useless and incorrect
problem solved
qed or whatever

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Infinity/1 * 1/Infinity = 1 AND = Infinity
^that's a fraction
Infinity/1 * 2/Infinity = 2 = Infinity
1 = Infinity
2 = Infinity
1 = 2
This means that math is undefined. All science is based off of math. Life is an illusion.
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roger- wrote:
Infinity/1 * 1/Infinity = 1 AND = Infinity
^that's a fraction
Infinity/1 * 2/Infinity = 2 = Infinity
1 = Infinity
2 = Infinity
1 = 2
This means that math is undefined. All science is based off of math. Life is an illusion.
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(infinity/infinity) is not equal to infinity.
(infinity/1) * (2/infinity) is not equal to 2.
Check your math.
Last edited by Kileymeister (2010-12-19 21:27:25)
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kayybee wrote:
This is definitely not true.
Code:
x= x+1 -x -x 0= 1 +x +x x= 1+x +y +y x+y=1+x+y
Yeah... I got nothin
I know it's not possible, I just like being argumentative.
Last edited by Aidan (2010-12-19 21:27:09)
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Well lets rearrange the equation.
x = x + 1
Eliminate the x'es (One on each side so we can do it)
0 = 1
On another note 0 does = 1
0 * 0 = 1 * 0
Eliminate one zero from each side
0 = 1
For the first equation the only thing I can think of that would fit would be infinity and to even get into any of these situations you have to divide by zero. Even if it is 0/0.
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midnightleopard wrote:
X=X+1. How can a number equal itself plus 1? Would this be the formula for infinity?
That gives you 0=1, so the solution for X is a null (empty) set. Simple.
But, no, it wouldn't be the "formula" for infinity, because then you can manipulate it to do all sorts of weird things.
Now, another question.
1/0
Could THAT be the "formula" for infinity?
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antimonyarsenide wrote:
midnightleopard wrote:
X=X+1. How can a number equal itself plus 1? Would this be the formula for infinity?
That gives you 0=1, so the solution for X is a null (empty) set. Simple.
But, no, it wouldn't be the "formula" for infinity, because then you can manipulate it to do all sorts of weird things.
Now, another question.
1/0
Could THAT be the "formula" for infinity?
No, because 0 * infinity is equal to 0. It's not possible for zero to be fit into a 1.
Because, after all, division is simply how many times a number fits into another. 0 never fits into a number, ever.
Technically not even 0/0 works, because inversely, that is equal to literally every number ever, and therefor undefined. Any number besides 0 is just undefined.
Last edited by Kileymeister (2010-12-19 21:43:01)
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kayybee wrote:
OR...
Code:
x=x+1 0=1 0^0=1^0 undefined=undefinedZero is weird, isn't it...
1^0 still equals 1. Ninja'd \/
On an unrelated note to the above:
My assumption on 0 divided by 0 wrote:
0/0 = every number in existence ∴= undefined.
Last edited by Kileymeister (2010-12-19 21:54:15)
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kayybee wrote:
OR...
Code:
x=x+1 0=1 0^0=1^0 undefined=undefinedZero is weird, isn't it...
Actually...
x = x + 1 0 = 1 0 ^ 0 = 1 ^ 0 undefined != 1
Darn it! Ninja'd!
Last edited by Harakou (2010-12-19 21:50:59)
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set x=0 and second x = 1
x = x-1
0= 1-1
0 = 0
This just proves that nothing is impossible :cool:
EDIT: I didn't know people still Ninja'd :o
Last edited by steppenwulf (2010-12-19 22:17:46)
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steppenwulf wrote:
set x=0 and second x = 1
x = x-1
0= 1-1
0 = 0
This just proves that nothing is impossible![]()
But x is always the same value. It would have to be X=Y-1 (or vice versa), which is a valid function.
Last edited by Kileymeister (2010-12-19 22:17:58)
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Kileymeister wrote:
steppenwulf wrote:
set x=0 and second x = 1
x = x-1
0= 1-1
0 = 0
This just proves that nothing is impossible![]()
But x is always the same value. It would have to be X=Y-1, which is a valid function.
I was just kidding lol.
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I guess it has to be infinity because:
∞=∞+1 so x=∞
But it doesn't really count since ∞ isn't actually a number.
Last edited by werdna123 (2010-12-20 02:52:35)
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It's true that ∞ = ∞+1, but...
Last edited by mathematics (2010-12-20 03:05:12)
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