scimonster wrote:
poemon1 wrote:
LiFaytheGoblin wrote:
why do you do (193- 12)-(193-7) = 5 ?
this would be (a²+b² - a) - (a² + b² - b)
I thought you would calculate it with this phythagoras thing a²+b²=c²? but maybe I understood it wrong, english math is new for me
EDIT: oh, I just saw what scimonsters wrote...Idk. It's just what I learned in my 6th grade year.
I'm in 8th grade, and learned the Pythagorean theorem straight from Khan Academy.
Well, i'm in the advanced class now, i also know trig.
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I love maths, so at the moment, I'm thinking about studying it later...
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That looks cool! I know a bit of trig, but all that knowledge goes to SIN, COS, ASIN, ACOS, and maybe soon TAN.
Hey, can you figure this equation out? It's a bit complex, through. The answer is not a real number.
Question: What is x?
Equation: squared (x) = -1
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trinary wrote:
^ i, obviously...
Although -i could also be correct...
Interesting.
I learn trig from Khan Academy.
We're not allowed to do so in school.
I also learned everything I know about trig from Khan academy. I convinced my teacher to teach sine cosine and tangent in class.
Back on topic with the mathematical equations
78x+56/y-yx=558+2/9
what is x?
what is y?
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My friend made an equation, it offended me.
Men = Money * Money
Time = Money, so men = Money^2
Money is the root of all evil, so Money = √evil
Which means that Money^2 = (√evil)^2 = evil
So that:
Men = evil
as i said, i was offended.
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TorbyFork234 wrote:
trinary wrote:
^ i, obviously...
Although -i could also be correct...
Interesting.
I learn trig from Khan Academy.
We're not allowed to do so in school.I also learned everything I know about trig from Khan academy. I convinced my teacher to teach sine cosine and tangent in class.
Back on topic with the mathematical equationsCode:
78x+56/y-yx=558+2/9what is x?
what is y?
I have no clue...what is leg 1 if the hypotenuse is 60 and the leg2 is 30 O_O
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poemon1 wrote:
scimonster wrote:
poemon1 wrote:
Idk. It's just what I learned in my 6th grade year.I'm in 8th grade, and learned the Pythagorean theorem straight from Khan Academy.
Well, i'm in the advanced class now, i also know trig.
...Good for you?
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What's this Khan Academy thingy everyone's talking about? I feel left out :'(
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at first i thought i might be the one to open this type of discussion. weird.
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I saw a logarithm on this page, and I realized: I forgot to do my math homework. D:
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poemon1 wrote:
Ok, Here is a fun one:
pick any number and multiply by two. add 5. multiply by 50. if you have had your birth day, add 1762, else add 1761. subtract the total by your 4-digit birth year, and the first number is what you chose, and the last digit(s) are your age!
That's scary. it worked!
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poemon1 wrote:
what is leg 1 if the hypotenuse is 60 and the leg2 is 30 O_O
Simple.
900 + x^2 = 3600
3600 - 900 = 2700
√2700 = 6√75
and 6√75 is approximately 51.961525
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x^x*y+3*48=22416
If you are reading this please don't tell anyone or post the answer. x=4 and y=87. and please don't quote.
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peomon1: 1+4+9+16+25+36+49=140
TobyFork: y = 22272/x^x
x = log(base x) of (22272/y)
x = log(22272/y)/log(x)
x*log(x) = log(22272/y)
this isn't going anywhere...
peonom1 (earlier): Why this works:
pick any number: x
multiply by 2: 2x
add 5: 2x + 5
multiply by 50: 100x + 250
add 1762/1761: 100x + 2011 OR 100x +2012
subtract birth year (any year say...1971): 100x + your age (2012-1971 = 41 in this case)
provided you're younger than 100, this will work . If not...well...it might mess up a bit . The key is the 100x because what that really does is add on 2 zeros so that you can put any two digit number, like an age, in those digits.
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veggieman001 wrote:
poemon1 wrote:
what is leg 1 if the hypotenuse is 60 and the leg2 is 30 O_O
Simple.
900 + x^2 = 3600
3600 - 900 = 2700
√2700 = 6√75
and 6√75 is approximately 51.961525
Actually, you can simplify that even further because 75 is divisible by 25, so it should actually be 30√3 which does indeed =51.961525
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echs wrote:
The-Whiz wrote:
5=ln((2X)^2.5)
Find xHmm, nice one.
Assuming x is positive, 2.5 log(x) = 3.26713.
Although the real solution figures to x ≈ 3.69453.
This one was a bit tricky.
The whole process is actually:
5 = ln((2X)^2.5) use law of log powers
5 = 2.5*ln(2X)
2 = ln(2X)
2X = e^2
X = (e^2)/2
X = 3.694528...
This way is a lot easier to read and keeps it theoretical until you've solved completely for x making calculations more accurate although it really only makes a difference around the quadrillionth's place .
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AtomicBawm3 wrote:
veggieman001 wrote:
poemon1 wrote:
what is leg 1 if the hypotenuse is 60 and the leg2 is 30 O_O
Simple.
900 + x^2 = 3600
3600 - 900 = 2700
√2700 = 6√75
and 6√75 is approximately 51.961525Actually, you can simplify that even further because 75 is divisible by 25, so it should actually be 30√3 which does indeed =51.961525
Oh yeah lol
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