Scratch

This already hurts...

samurai768 wrote:

1/9x, I think 

Please explain 

This is algebra right? If I assume x is an algebraic letter, than 3x squared would be 9x.

So what is the reciprocal for 9x? Or rather, what is the reciprocal for 9? Obviously. 1/9.

So the answer is 1/9x.

I'm not very good with reciprocals because I heard about them exactly 3 seconds ago, but I try.

wmays wrote:

helltank wrote:

This is algebra right? If I assume x is an algebraic letter, than 3x squared would be 9x.

So what is the reciprocal for 9x? Or rather, what is the reciprocal for 9? Obviously. 1/9.

So the answer is 1/9x.

I'm not very good with reciprocals because I heard about them exactly 3 seconds ago, but I try.

OBJECTION!

Sorry, but I had to say that.

That is incorrect because 3x = 3 times x, so 3x squared equals 3 squared times x squared. So, that's 9x squared, so it's 1/9x to the negative second. x to the negative second equals x/x.

lol 

I got the same thing as you.

I'm scared. I don't understand anything you guys are saying.

JJROCKER wrote:

I need help with this- (x+1)^4

(x+1 to the fourth power)

That's a bit of binomial expansion. 

Using the formula


you come to the conclusion that (x+1)^4 =


Simple! ;D

JJROCKER wrote:

cpumaster930 wrote:

JJROCKER wrote:

I need help with this- (x+1)^4

(x+1 to the fourth power)

That's a bit of binomial expansion. 

Using the formula
http://upload.wikimedia.org/math/d/4/5/ … 46d2c8.png

you come to the conclusion that (x+1)^4 =
http://www3.wolframalpha.com/Calculate/ … 9&h=18

Simple! ;D

How would I plug it in?

Here's a simpler example: (x+5)^2.
First, find the exponent that the binomial is being raised to (n).  In this case, it's 2, so you'll have 3 terms (always one more than the exponent).
Next, fill in the coefficients for each term, which are shown in a row of Pascal's triangle:

Find the row with three terms (the third one of course).  The coefficients will be 1, 2, 1.
Number your terms above for easy reference.  Start with 0.  This we'll call r.
In each term, raise the first part of the binomial to the n-r power and the second part of the binomial to the r power.
Finally, simplify each term by multiplying everything together, and add all the terms.

For our example, (x+5)^2:
Write coefficients.
1_____ + 2_____ + 1______
Number the terms with r-values.
     0          1            2
1_____ + 2_____ + 1______
Raise the first part of the binomial (x, in this case) to the n-r power.
     0            1              2
1(x^2)__ + 2(x^1)__ + 1(x^0)__
Raise the second part of the binomial to the r power.
       0                1                 2
1(x^2)(5^0) + 2(x^1)(5^1) + 1(x^0)(5^2)
Simplify each term.
5x^2          + 10x          + 25
String everything together.
5x^2+10x+25

And that's about it.
If you're still confused, let me know 

JJROCKER wrote:

cpumaster930 wrote:

JJROCKER wrote:

How would I plug it in?

Here's a simpler example: (x+5)^2.
First, find the exponent that the binomial is being raised to (n).  In this case, it's 2, so you'll have 3 terms (always one more than the exponent).
Next, fill in the coefficients for each term, which are shown in a row of Pascal's triangle:
http://upload.wikimedia.org/wikipedia/c … ngle_5.svg
Find the row with three terms (the third one of course).  The coefficients will be 1, 2, 1.
Number your terms above for easy reference.  Start with 0.  This we'll call r.
In each term, raise the first part of the binomial to the n-r power and the second part of the binomial to the r power.
Finally, simplify each term by multiplying everything together, and add all the terms.

For our example, (x+5)^2:
Write coefficients.
1_____ + 2_____ + 1______
Number the terms with r-values.
     0          1            2
1_____ + 2_____ + 1______
Raise the first part of the binomial (x, in this case) to the n-r power.
     0            1              2
1(x^2)__ + 2(x^1)__ + 1(x^0)__
Raise the second part of the binomial to the r power.
       0                1                 2
1(x^2)(5^0) + 2(x^1)(5^1) + 1(x^0)(5^2)
Simplify each term.
5x^2          + 10x          + 25
String everything together.
5x^2+10x+25

And that's about it.
If you're still confused, let me know 

Thanks 

No problem 
I'm tutoring freshmen and sophomores (and possibly juniors) in math this year, so this is good practice 
If you need help with anything else, feel free to ask. ;D

cpumaster930 wrote:

JJROCKER wrote:

cpumaster930 wrote:

Here's a simpler example: (x+5)^2.
First, find the exponent that the binomial is being raised to (n).  In this case, it's 2, so you'll have 3 terms (always one more than the exponent).
Next, fill in the coefficients for each term, which are shown in a row of Pascal's triangle:
http://upload.wikimedia.org/wikipedia/c … ngle_5.svg
Find the row with three terms (the third one of course).  The coefficients will be 1, 2, 1.
Number your terms above for easy reference.  Start with 0.  This we'll call r.
In each term, raise the first part of the binomial to the n-r power and the second part of the binomial to the r power.
Finally, simplify each term by multiplying everything together, and add all the terms.

For our example, (x+5)^2:
Write coefficients.
1_____ + 2_____ + 1______
Number the terms with r-values.
     0          1            2
1_____ + 2_____ + 1______
Raise the first part of the binomial (x, in this case) to the n-r power.
     0            1              2
1(x^2)__ + 2(x^1)__ + 1(x^0)__
Raise the second part of the binomial to the r power.
       0                1                 2
1(x^2)(5^0) + 2(x^1)(5^1) + 1(x^0)(5^2)
Simplify each term.
5x^2          + 10x          + 25
String everything together.
5x^2+10x+25

And that's about it.
If you're still confused, let me know 

Thanks 

No problem 
I'm tutoring freshmen and sophomores (and possibly juniors) in math this year, so this is good practice 
If you need help with anything else, feel free to ask. ;D

I have a few other questions if that is ok with you.

cpumaster930 wrote:

JJROCKER wrote:

cpumaster930 wrote:

No problem 
I'm tutoring freshmen and sophomores (and possibly juniors) in math this year, so this is good practice 
If you need help with anything else, feel free to ask. ;D

I have a few other questions if that is ok with you.

Sure, ask away.  It's not like I'm doing anything else 

On a side note, I have a small favor to ask of you: I worked quite hard on SCR, the game currently in my signature.  If you wouldn't mind, could you please check it out, and if you like it, consider linking to it in one of your projects? ^^ Any publicity would really help because I really want this project to make the front page ;D

So...what's your question? 

I'll definately look at it and do that for you. Any projects you want me to view I will.

Thanks 

cpumaster930 wrote:

JJROCKER wrote:

cpumaster930 wrote:

Sure, ask away.  It's not like I'm doing anything else 

On a side note, I have a small favor to ask of you: I worked quite hard on SCR, the game currently in my signature.  If you wouldn't mind, could you please check it out, and if you like it, consider linking to it in one of your projects? ^^ Any publicity would really help because I really want this project to make the front page ;D

So...what's your question? 

I'll definately look at it and do that for you. Any projects you want me to view I will.

Thanks 

So...do you have any more questions? 

Yeah, hold on...

Are you good at Physics?

cpumaster930 wrote:

JJROCKER wrote:

cpumaster930 wrote:

So...do you have any more questions? 

Yeah, hold on...

Are you good at Physics?

Not particularly, but I'm taking Physics this year.
I've taken Bio and Chem though 

I'm taking Physics this year also.

How about...

Reduce the Fraction: 4x(x+2)^2-2x^2(x+2)/(x+2)^3