Scratch

x - 1 = -1
   +1   +1
x = 0.


I AM A GENIUS.

throughthefire wrote:

3x^2 + 6x + 6 = 0
no solution!

There actually is a real solution, but it's irrational so you can't find it out by factoring. To know if you can factor a quadratic trinomial easily, use the discriminant test: b² - 4ac where the constants abc are present in ax² + bx + c. Note that it's the part of the quadratic formula that's under the square root 

Anyway, the answer to the equation is

S = { (-2 +/- 2root2) / 2 }

if you can read that    and if it's wrong, I'm sorry. I didn't even do it properly.

LS97 wrote:

meew0 wrote:

x-1 = b+1
x*2 = b*-2
What is x and what is b?

I'll be happy to solve it, just to keep me busy (school exams are over, I have nothing to do).
Note that I did it on paper and then transferred the working to here, so it's a bit messy. Oh, and I did it my way. I know it's pretty long but it's easy.

Code:

x - 1 = b + 1
x = b + 2

2x = -2b
x = -b

Join the two and get rid of x for now

b + 2 = -b
2b = -2
b = -1

Plug b back into the original

x - 1 = (-1) + 1
x = 1

S = {x = 1, b = -1}

Check it

1 - 1 = -1 + 1
0 = 0
yay!

Right! 

^^ anyone?

-6.309
At least MSM says that.

LS97 wrote:

throughthefire wrote:

3x^2 + 6x + 6 = 0
no solution!

There actually is a real solution, but it's irrational so you can't find it out by factoring. To know if you can factor a quadratic trinomial easily, use the discriminant test: b² - 4ac where the constants abc are present in ax² + bx + c. Note that it's the part of the quadratic formula that's under the square root 

Anyway, the answer to the equation is

S = { (-2 +/- 2root2) / 2 }

if you can read that    and if it's wrong, I'm sorry. I didn't even do it properly.

Actually, it's not technically a real solution, it's an imaginary solution.  That is, it contains the square root of a negative number (in this case, it comes out as sqrt(-4) or 2sqrt(-1) which is 2i)

@LS97:  I can do it, but I'll need to get some paper and I really don't feel like doing that.

meew0 wrote:

LS97 wrote:

meew0 wrote:

-6.309
At least MSM says that.

  To which one? If it's to mine, no way.

To yours...
As I said, I didn't solve it, Microsoft Mathematics solved it...

Yeah -- Really weird. I've had good experiences with MSM until now...
EDIT: I put the equation in and it did solve it well. Try again. But don't post the answer if you didn't work it out by hand!

Last edited by LS97 (2011-06-17 14:53:15)

LS97 wrote:

meew0 wrote:

LS97 wrote:

  To which one? If it's to mine, no way.

To yours...
As I said, I didn't solve it, Microsoft Mathematics solved it...

Yeah -- Really weird. I've had good experiences with MSM until now...
EDIT: I put the equation in and it did solve it well. Try again. But don't post the answer if you didn't work it out by hand!

I tried it again and it gave me the same result...

Oh, so sorry, I somehow imagined a 4 in that original equation. You see:

x = -b +/- √b²-4ac all over 2a

i thought b in the b² was 4...

Okay, I know this sounds weird, but for LS97's question I got -11 and -1

Ugh... I never learned how to solve that kind of problem... I admit defeat.

@skyline: sorry, but you missed a ton... A factorial (9!) is multiplied, not added
A square is a number times itself, not times 2. look at my answers (above yours)

wulfmaster wrote:

16Skittles wrote:

@skyline: sorry, but you missed a ton... A factorial (9!) is multiplied, not added
A square is a number times itself, not times 2. look at my answers (above yours)

Why do you have ssss' name in your signature?

you don't play minecraft do you...