Harakou wrote:
JJROCKER wrote:
Harakou wrote:
5! = 120
Not that hard. Let's see now, how about this? (Simplify; no calculators now! And yes, the answer is a whole number.)
(5log(125))/(log(2.5) + log(2))I have no clue, whats log?
log(x) is a logarithm of x with base 10. A logarithm is the inverse of a exponent. For a logarithm of x with base b and result a, b^a = x. So for example, log(100) = 2.
Of course, now that I posted that, I realized that it wasn't exactly the expression I intended. A better one that should be relatively easy to solve assuming you know the properties of logarithms would be this:
(125log(5))/(log(2.5) + log(2))
The basic properties are as follows:log(a) + log(b) = log(ab)
log(a) - log (b) = log(a/b)
a * log(x) = log(x^a)
log (base b) of x = log(x)/log(b) (It's hard to express the base here because I don't have access to subscripts.)Of course, I kinda feel like I'm intruding on your thread here. Not sure if you meant this as a specific discussion about factorials or a place to talk about mathematics in general and quiz each other.
![]()
Im still really confused on log. What is ^ mean?

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JJROCKER wrote:
Harakou wrote:
JJROCKER wrote:
I have no clue, whats log?log(x) is a logarithm of x with base 10. A logarithm is the inverse of a exponent. For a logarithm of x with base b and result a, b^a = x. So for example, log(100) = 2.
Of course, now that I posted that, I realized that it wasn't exactly the expression I intended. A better one that should be relatively easy to solve assuming you know the properties of logarithms would be this:
(125log(5))/(log(2.5) + log(2))
The basic properties are as follows:log(a) + log(b) = log(ab)
log(a) - log (b) = log(a/b)
a * log(x) = log(x^a)
log (base b) of x = log(x)/log(b) (It's hard to express the base here because I don't have access to subscripts.)Of course, I kinda feel like I'm intruding on your thread here. Not sure if you meant this as a specific discussion about factorials or a place to talk about mathematics in general and quiz each other.
![]()
Im still really confused on log. What is ^ mean?
^ is "to the power of"
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JJROCKER wrote:
Harakou wrote:
JJROCKER wrote:
I have no clue, whats log?log(x) is a logarithm of x with base 10. A logarithm is the inverse of a exponent. For a logarithm of x with base b and result a, b^a = x. So for example, log(100) = 2.
Of course, now that I posted that, I realized that it wasn't exactly the expression I intended. A better one that should be relatively easy to solve assuming you know the properties of logarithms would be this:
(125log(5))/(log(2.5) + log(2))
The basic properties are as follows:log(a) + log(b) = log(ab)
log(a) - log (b) = log(a/b)
a * log(x) = log(x^a)
log (base b) of x = log(x)/log(b) (It's hard to express the base here because I don't have access to subscripts.)Of course, I kinda feel like I'm intruding on your thread here. Not sure if you meant this as a specific discussion about factorials or a place to talk about mathematics in general and quiz each other.
![]()
Im still really confused on log. What is ^ mean?
"To the power of--"
Basiacally, 9^2=9²=81
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scratch_yoshi wrote:
JJROCKER wrote:
Harakou wrote:
log(x) is a logarithm of x with base 10. A logarithm is the inverse of a exponent. For a logarithm of x with base b and result a, b^a = x. So for example, log(100) = 2.
Of course, now that I posted that, I realized that it wasn't exactly the expression I intended. A better one that should be relatively easy to solve assuming you know the properties of logarithms would be this:
(125log(5))/(log(2.5) + log(2))
The basic properties are as follows:
Of course, I kinda feel like I'm intruding on your thread here. Not sure if you meant this as a specific discussion about factorials or a place to talk about mathematics in general and quiz each other.![]()
Im still really confused on log. What is ^ mean?
"To the power of--"
Basiacally, 9^2=9²=81
Ohhhhh I get it

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JJROCKER wrote:
so 8^2=64
Yup!
JJROCKER wrote:
What math are you taking? Does it help being in a higher math level with scratch?
I'm taking Pre-Calculus right now. I'd say it can come in handy; trigonometry is particularly useful in some situations and a good understanding of algebra can be useful in developing some algorithms and equations in scripts.
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Harakou wrote:
JJROCKER wrote:
so 8^2=64
Yup!
JJROCKER wrote:
What math are you taking? Does it help being in a higher math level with scratch?
I'm taking Pre-Calculus right now. I'd say it can come in handy; trigonometry is particularly useful in some situations and a good understanding of algebra can be useful in developing some algorithms and equations in scripts.
Thats good.

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JJROCKER wrote:
Harakou wrote:
JJROCKER wrote:
so 8^2=64
Yup!
JJROCKER wrote:
What math are you taking? Does it help being in a higher math level with scratch?
I'm taking Pre-Calculus right now. I'd say it can come in handy; trigonometry is particularly useful in some situations and a good understanding of algebra can be useful in developing some algorithms and equations in scripts.
Thats good.
What about you?
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Harakou wrote:
JJROCKER wrote:
Harakou wrote:
JJROCKER wrote:
so 8^2=64
Yup!
I'm taking Pre-Calculus right now. I'd say it can come in handy; trigonometry is particularly useful in some situations and a good understanding of algebra can be useful in developing some algorithms and equations in scripts.Thats good.
What about you?
Now I am a little embarrassed but I am starting Algebra I

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JJROCKER wrote:
Harakou wrote:
JJROCKER wrote:
Thats good.What about you?
Now I am a little embarrassed but I am starting Algebra I
I'm at the end of Alg. 1 XD
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I don't even think I'm IN algebra yet XD MISSING POSTS ALERT!!
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What grade are you in, anyway?
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Harakou wrote:
Yes, it would be 1,600. Would you be able to solve something like this?
(4(x + 5))/6 = 20
25 right? I was a little confused on how to do it though. Do you think you could explain it step by step?

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