So if Momentum =M*V
Then if Velocity= ΔX/ΔT
What does Δ Equal? I think its a var that messurs change with in speed. Any one able to tell me? Im trying to find out how fast things can goo with these equalsions...
What does Δ mean?
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It's somewhere in here.
EDIT: It means change or rate of change.
Last edited by Kileymeister (2010-11-28 19:45:14)
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Kileymeister wrote:
It's somewhere in here.
EDIT: It means change or rate of change.
Average? Thats all im getting, im an 11 trying to understand all this
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recycle49 wrote:
Kileymeister wrote:
It's somewhere in here.
EDIT: It means change or rate of change.Average? Thats all im getting, im an 11 trying to understand all this
And I am a 10 NOT understanding this XD.
Well, a 9 and 364 days.
Last edited by werdna123 (2010-11-30 06:04:45)
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recycle49 wrote:
So if Momentum =M*V
Then if Velocity= ΔX/ΔT
What does Δ Equal? I think its a var that messurs change with in speed. Any one able to tell me? Im trying to find out how fast things can goo with these equalsions...
What does Δ mean?
That's delta, it has no value. It's just a symbol showing how to read the equation. In this case, try reading it as "difference", or better yet, "change". Therefore:
Velocity = (change in distance)/(change in time)
Where X = distance traveled, and T = time.
Does this help?

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cheddargirl wrote:
recycle49 wrote:
So if Momentum =M*V
Then if Velocity= ΔX/ΔT
What does Δ Equal? I think its a var that messurs change with in speed. Any one able to tell me? Im trying to find out how fast things can goo with these equalsions...
What does Δ mean?That's delta, it has no value. It's just a symbol showing how to read the equation. In this case, try reading it as "difference", or better yet, "change". Therefore:
Velocity = (change in distance)/(change in time)
Where X = distance traveled, and T = time.
Does this help?
Yes it does, now it makes so much more sence, i understood to equasion but the delta messed me up
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Delta isn't a variable. It's more like a function, but not exactly. It represents change. So ΔM would mean change in M, and so forth.
EDIT: What cheddargirl said
Last edited by antimonyarsenide (2010-12-08 22:00:36)
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Think about this: If you start at 10 units of velocity and in one second you go to 20 units of velocity, you've changed 10 units in one second. Delta is not only the change in velocity, but also the one second. It really shouldn't be in the equation at all. The equation should look more like: Velocity1-Velocity2/Time1-Time2, but that's basically what's implied by Delta.
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OH! mind melting!
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