floatingmagictree wrote:
littletonkslover wrote:
Most useful: Broadcast
Least Useful: Forever...?Forever is extremely useful. Of course, you really wouldn't need it in one of your animations, unless you were looping something.
I'm not a fan of random looping animations. After seeing the stick man blowing up 30 times.....

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littletonkslover wrote:
floatingmagictree wrote:
littletonkslover wrote:
Most useful: Broadcast
Least Useful: Forever...?Forever is extremely useful. Of course, you really wouldn't need it in one of your animations, unless you were looping something.
I'm not a fan of random looping animations. After seeing the stick man blowing up 30 times.....
Where did you see a stickman blow up 30 times?
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floatingmagictree wrote:
littletonkslover wrote:
floatingmagictree wrote:
Forever is extremely useful. Of course, you really wouldn't need it in one of your animations, unless you were looping something.
I'm not a fan of random looping animations. After seeing the stick man blowing up 30 times.....
Where did you see a stickman blow up 30 times?
*waz example*

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littletonkslover wrote:
floatingmagictree wrote:
littletonkslover wrote:
I'm not a fan of random looping animations. After seeing the stick man blowing up 30 times.....Where did you see a stickman blow up 30 times?
*waz example*
?
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PinballFreak1969 wrote:
() MOD () is very useful sometimes.
When? When do you need the remainder of something?
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Getting tired every hundred steps and needing to rest.
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archmage wrote:
No, its definitely forever wait until. I think the scratch team confirmed it in some post.
*Ahem*
Run in single stepping. They both do *EXACTLY* the same thing. This is one of the most pointless arguments I've ever had.
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floatingmagictree wrote:
littletonkslover wrote:
floatingmagictree wrote:
Where did you see a stickman blow up 30 times?*waz example*
?
XD The stick man was an example.

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Kileymeister wrote:
Most Useful: Broadcast (it isn't most necessary, people)
Least Useful: ( )mod( ) I've never had to use it. Ever. Forever If starts bad habits but can be useful once in a while.
Forever if doesn't start bad habits...?
And mod is EXTREMELY useful!
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PinballFreak1969 wrote:
Getting tired every hundred steps and needing to rest.
First off, how?
If (steps)mod(100)=0?
Ok,
If (steps)=100. A lot simpler.
Last edited by Kileymeister (2010-03-31 21:27:42)
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Kileymeister wrote:
PinballFreak1969 wrote:
Getting tired every hundred steps and needing to rest.
First off, how?
If (steps)mod(100)=0?
Ok,
If (steps)=100. A lot simpler.
no, but look at this:
set (steps) to ((steps) mod (100))
if ((steps)=(99))
Will never go above 99
And plus, your example doesn't get tired every hundred steps, it gets tired AT 100 steps, not 200, not 300, not 400, just 100.
Last edited by nXIII (2010-03-31 21:31:15)
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nXIII wrote:
Kileymeister wrote:
PinballFreak1969 wrote:
Getting tired every hundred steps and needing to rest.
First off, how?
If (steps)mod(100)=0?
Ok,
If (steps)=100. A lot simpler.no, but look at this:
set (steps) to ((steps) mod (100))
if ((steps)=(99))
Will never go above 99
And plus, your example doesn't get tired every hundred steps, it gets tired AT 100 steps, not 200, not 300, not 400, just 100.
But then it resets to 0.
If (steps)=100
set (steps) to 0.
EDIT: Wait a minute... this block could actually be useful... nevermind what I said before.
Last edited by Kileymeister (2010-03-31 21:38:07)
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Kileymeister wrote:
nXIII wrote:
Kileymeister wrote:
First off, how?
If (steps)mod(100)=0?
Ok,
If (steps)=100. A lot simpler.no, but look at this:
set (steps) to ((steps) mod (100))
if ((steps)=(99))
Will never go above 99
And plus, your example doesn't get tired every hundred steps, it gets tired AT 100 steps, not 200, not 300, not 400, just 100.But then it resets to 0.
If (steps)=100
set (steps) to 0.
EDIT: Wait a minute... this block could actually be useful... nevermind what I said before.
Rounding Up/Down:
(( someFloat <-> (( someFloat <mod> 1 )) ))[/blocks]
rounds down
(( someFloat <+> (( 1 <-> (( someFloat <mod> 1 )) )) ))[/blocks]
rounds up
Last edited by nXIII (2010-03-31 21:56:18)
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No more proving
[blocks](( 0 <mod> 0 ))[/blocks]
useful.
Back to talking about useful/useless blocks.
Last edited by PinballFreak1969 (2010-03-31 22:12:23)
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Forever if could be done without, but I don't think any blocks are completely useless...
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