Scratch
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#1 2013-02-09 12:38:45
Add Exponent Operator
As the title says, Scratch could use the ^ operator. As in:
<() ^ ()>And no, there is no valid workaround involving the repeat block. Reason why:
Say I want the cube root of a number for some reason. With the block, I could just do
<(number) ^ ((1)/(3))>However,
repeat((1)/(3)) doSomething endis not going to work for obvious reasons. Scratch will not run something 1/3 of a time.
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#2 2013-02-09 13:04:31
- shadowmouse
- New Scratcher
- Registered: 2013-02-03
- Posts: 100+
Re: Add Exponent Operator
Support! This is something that can only be done in BYOB, and even then it's not that easy and it's useful for finding distances as well as other things.
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#3 2013-02-09 18:15:01
Re: Add Exponent Operator
Support! And thank you for teaching me how to find the square root/cube root of a number. I've been trying to find how forever and that's ALL it takes?!
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#4 2013-02-10 05:48:28
Re: Add Exponent Operator
ImagineIt wrote:
Support! And thank you for teaching me how to find the square root/cube root of a number. I've been trying to find how forever and that's ALL it takes?!
Yeah, sqrt(x) is x^(1/2) and cube root of x is x^(1/3) etc.
I think you cover it in algebra so you might not have learned it.
I think there's a way to do exponents with logarithms as a workaround, but little kids probably won't get that so a ()^() block might be nice.
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#6 2013-02-12 12:12:39
- shadowmouse
- New Scratcher
- Registered: 2013-02-03
- Posts: 100+
Re: Add Exponent Operator
What is the workaround? Just asking because I'm doing a project involving algebra in byob and an exponent block would be useful.
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Hello Scratch 2.0! 
#8 2013-02-12 19:09:28
Re: Add Exponent Operator
shadowmouse wrote:
What is the workaround? Just asking because I'm doing a project involving algebra in byob and an exponent block would be useful.
kayybee wrote:
Yeah, sqrt(x) is x^(1/2) and cube root of x is x^(1/3) etc.
I think you cover it in algebra so you might not have learned it.
I think there's a way to do exponents with logarithms as a workaround, but little kids probably won't get that so a ()^() block might be nice.
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#9 2013-02-12 22:11:54
Re: Add Exponent Operator
Mokat wrote:
shadowmouse wrote:
What is the workaround? Just asking because I'm doing a project involving algebra in byob and an exponent block would be useful.
kayybee wrote:
Yeah, sqrt(x) is x^(1/2) and cube root of x is x^(1/3) etc.
I think you cover it in algebra so you might not have learned it.
I think there's a way to do exponents with logarithms as a workaround, but little kids probably won't get that so a ()^() block might be nice.
I think you're missing the point.
shadowmouse wrote:
What is the workaround? Just asking because I'm doing a project involving algebra in byob and an exponent block would be useful.
There.
Last edited by lalala3 (2013-02-12 23:01:33)
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#10 2013-02-13 03:35:35
Re: Add Exponent Operator
since everyone seems to be all excited about it, I guess I should post it.
I actually don't know/forgot it so ill have to think about it for a while.
Okay, I think I got it. it only took 6 minutes. Probably would've been faster searching I but oh well.
I think this should work. (you can use 10^ and log, or e^ and ln)
e^[y*ln(x)]=x^y
=10^[y*log(x)]
You might have to round it cause it'll be a bit off (like a billionth or a trillionth or so)
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#11 2013-02-13 05:39:02
- shadowmouse
- New Scratcher
- Registered: 2013-02-03
- Posts: 100+
Re: Add Exponent Operator
Thanks Kayybee, I think Scratch rounds once it gets to ceratin amount of decimal places anyway.
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