Scratch

Bump!

Yuck.

Sorry, I don't support.

These blocks don't work like you think they do.

In your first example, (Item [2] of [list v]) returns the contents of the second entry of your list... as a string.  You can't set a string to a value.  You can only set a string variable to a value.  You'd need to specify it differently.  As shown, it is specified as what is stored in your list, not your list itself.

Pretty sure sure Wes is the only one that understood me.

I guess more explaining is in order:

There are NO workarounds for this...
This would work flawlessly. I think. lol.

In the first example there is already a variable named [insert what item 2 of "list" is here].

set (item [2] of [list v]) to [0]

delete [10] of (variable)

Last edited by CheeseMunchy (2013-01-17 20:24:58)

^^(item [# v] of [list v]) is a "reporter" block. It gives you the value of an item in a list; it is not a reference to that item in that list.

It makes more sense when you have the experience of working in what people 'round here call a "text-based language". This example is in Lua:

function number()
    return 1
end

number() = 3

The function number() returns a number: 1. What you're trying to do, is kinda like that last line, equivalent to this:

1 = 3

You're trying to set a number, and not a variable that perhaps holds that number, to another number. That's not possible. Try it out here; should give you a syntax error.

What you want to do is already possible with another Scratch block; see sonicfan12p's post.
____________

As for the other block, it's perfectly possible with 2.0's custom blocks.

define: delete (number) of (string); store in (variable) //it's not really like this in 2.0, but you get my point
if <(length of (string)) > (number)>
    stop script //nothing happens
end
set [newVariable v] to []
set [i v] to [1]
repeat (length of (string))
    if <not <(i) = (number)>> //to remove the specific letter from the string.
        set [newVariable v] to (join (newVariable) (letter (i) of (string)))
    end
    change [i v] by [1]
end
set (variable) to (newVariable) //apparently you won't be able to make reporter blocks in 2.0 (D:<), so I must resort to this ugly workaround.

Last edited by technoguyx (2013-01-17 21:07:50)

The reference is the reference to that value; a pointer to the location in the memory that contains the value. When you declare a variable:

set [foo v] to [bar]