Scratch

Nao

Tau No Better Dahn Pi

depends on what youre using it for and how you're using it
sometimes it is
sometimes it isnt

pi ftw

Why does tau have to replace pi
What's wrong with having both

RedRocker227 wrote:

0.9999... doesn't equal one

How so?  I can give proof of it.

0.9999 etc is nearly one, but therell always be an infinitely small piece missing
of course you could always dismiss this infinitely small piece as "zero" but whats the fun in that?
also if 0.9999 etc is one then what about 1/3 and other fractions which produce repeating decimals

RedRocker227 wrote:

Firedrake969 wrote:

RedRocker227 wrote:

0.9999... doesn't equal one

How so?  I can give proof of it.

Okay then

I'd like your explanation first.

777w wrote:

0.9999 etc is nearly one, but therell always be an infinitely small piece missing
of course you could always dismiss this infinitely small piece as "zero" but whats the fun in that?
also if 0.9999 etc is one then what about 1/3 and other fractions which produce repeating decimals

By the definition of infinity, you can't have that 1 at the end because of the infinite 0s.
1/3 = 0.333...
2/3 = 0.666...
3/3 = 1
Substitution:
0.333.... + 0.666.... = 0.9999...

RedRocker227 wrote:

Hm although I kind of contradicted myself
In another thread I said 0.000...1 doesn't exist, so then what would 1-0.999 be
Hmmmm

0.

Last edited by Firedrake969 (2013-01-04 21:27:00)

777w wrote:

Firedrake969 wrote:

zubblewu wrote:

0.9999 etc is nearly one, but therell always be an infinitely small piece missing
of course you could always dismiss this infinitely small piece as "zero" but whats the fun in that?
also if 0.9999 etc is one then what about 1/3 and other fractions which produce repeating decimals

By the definition of infinity, you can't have that 1 at the end because of the infinite 0s.
1/3 = 0.333...
2/3 = 0.666...
3/3 = 1
Substitution:
0.333.... + 0.666.... = 0.9999...

zubblewu didnt write that

Now he did.  c:  Fixed.

Firedrake969 wrote:

By the definition of infinity, you can't have that 1 at the end because of the infinite 0s.
1/3 = 0.333...
2/3 = 0.666...
3/3 = 1
Substitution:
0.333.... + 0.666.... = 0.9999...

thats a good method to prove this.

Too lazy to quote and crop the unrelated bits since I'm on my iPod and it takes ages but
Where you said (1/3)+(2/3)=3/3=0.333...+0.666...=0.999...=1, that's incorrect since I'd've thought there's no true value for 1/3, only approximations, I'm not entirely sure though

I'm still kind of undecided though, as far as I know there's no official answer and it's down to which set of proofs you believe basically

Last edited by RedRocker227 (2013-01-04 21:51:29)

Firedrake969 wrote:

RedRocker227 wrote:

Too lazy to quote and crop the unrelated bits since I'm on my iPod and it takes ages but
Where you said (1/3)+(2/3)=3/3=0.333...+0.666...=0.999...=1, that's incorrect since I'd've thought there's no true value for 1/3, only approximations, I'm not entirely sure though

I'm still kind of undecided though, as far as I know there's no official answer and it's down to which set of proofs you believe basically

Actually, 1/3 is a repeating decimal number, so it would be exactly 0.333333.... if you can call it exact.

But there's no correct way to write down 1/3 other than as a fraction, IMO that means you shouldn't be able to use what you claim to be its decimal equivalent in an equation or proof

lalala3 wrote:

RedRocker227 wrote:

0.9999... doesn't equal one

Yes it does. Allow me to prove it.
Let x=0.99999999...
Therefore, 10x=9.999999999...
Minus x equals 9
So, 10x-x=9, or 9x=9. x equals one.

Thanks for another proof.  :>