Scratch

bullelk12 · 2012-09-10 20:12:55

I need an AI to be able to tell if there are 4 1s or 2s or anything of the same value adjacent to each other within a list. Simple but very hard unless I'm mistaken. e.g. 011110. So now the AI has to determine if there are four numbers of the same value adjacent to each other. In the example there is, since there are four 1s.
If it's too hard or impossible to be able to tell with anything of the same value, then I still want to know how to do it with just 1s.

I can do the rest I just need to now how to that one part. But it CANNOT be manually done. That would take me an eternity to do.

danwoodski · 2012-09-10 20:28:00

I'm working on it...give me a few minutes...

bullelk12 · 2012-09-10 20:32:50

great!

danwoodski · 2012-09-10 20:36:22

This should work...

set [counter1 v] to [1]
set [current value v] to [n/a]
set [# of occurances v] to [0]
repeat (length of [list v] )  

if <(item (counter1) of [list v] ) = (current value)>

change [# of occurances v] by (1)
if <(# of occurances) > [2]> 

say (join (current value) [ has occured 4 times.]) for (2) secs
end

else

set [# of occurances v] to [0]
set [current value v] to (item (counter1) of [list v] )
end

change [counter1 v] by (1)
end

bullelk12 · 2012-09-10 20:38:01

That could work, I'll try it.

thx

bullelk12 · 2012-09-10 20:46:33

It worked. Credit to you man, I worked on that one for an hour. Came a ways but met with the same problem.

Last edited by bullelk12 (2012-09-10 20:52:04)

Scratch

archived forums

#1 2012-09-10 20:12:55

Tough list problem

#2 2012-09-10 20:28:00

Re: Tough list problem

#3 2012-09-10 20:32:50

Re: Tough list problem

#4 2012-09-10 20:36:22

Re: Tough list problem

#5 2012-09-10 20:38:01

Re: Tough list problem

#6 2012-09-10 20:46:33

Re: Tough list problem

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