Scratch

I don't know any python at all but this would be my guess:
Isn't * part of  a string? Imo you should treat it like a string :3
edit: you should ask on Coders' Shed 

Last edited by slinger (2012-04-17 03:34:10)

you need to import antigravity

number1 = raw_input("Please enter first number")

op = (raw_input("Please enter an operator, either x, +, - or /."))

number2 = (raw_input("Please enter a second number"))


print number1 + operator + number2


if op == '*':
    print number1 * number2
elif op == '+':
    print number1 + number2
elif op == '-':
    print number1 - number2
elif op == '/':
    print number1 / number2
else:
    print "operator is not valid"

three things:
you should put '' or "" around strings
you should put ':' after compound statements
you should put space around operators (and read PEP8 when you have time)

good luck! 

scimonster wrote:

slinger wrote:

I don't know any python at all but this would be my guess:
Isn't * part of  a string? Imo you should treat it like a string :3
edit: you should ask on Coders' Shed 

Yep, i was just going to say, it looks like a string.

Code:

number1 = raw_input("Please enter first number")

op = raw_input("Please enter an operator, either x, +, - or /.")

number2 = raw_input("Please enter a second number")


print number1+operator+number2


if op == "*"
    print number1*number2
elif op == "+"
    print number1+number2
elif op == "-"
    print number1-number2
elif op == "/"
    print number1/number2
else
    print "operator is not valid"

And are you sure the else if command is "elif"?

Yes, 'else if' is 'elif' in Python.

A variable cannot be an operator in python. It makes it confused.

EDIT: Wouldn't it make more sense to use a function in the end instead of that jumble of 'if's?

Last edited by -GizzardGulp- (2012-04-21 10:49:35)

Update it to Python 3 while you're at it.