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poemon1 · 2012-03-25 14:18:35

I am making mathematical equations to test my skill. Such as y-2x^4

Code:

 
y=2x^4

x=2
2*2=4 $^4= 4*4*4*4=256, thus y=256.

discuss math here !

werdna123 · 2012-03-25 14:19:55

I found that pretty easy. tongue

poemon1 · 2012-03-25 14:22:48

werdna123 wrote:
I found that pretty easy.

I know. Lol. Can you do this: y=x^x/(7^4/7)
x=2???

scimonster · 2012-03-25 14:25:42

poemon1 wrote:
werdna123 wrote:
I found that pretty easy.
I know. Lol. Can you do this: y=x^x/(7^4/7)
x=2???

y=0.01166

poemon1 · 2012-03-25 14:25:45

Ok, Here is a fun one:

pick any number and multiply by two. add 5. multiply by 50. if you have had your birth day, add 1762, else add 1761. subtract the total by your 4-digit birth year, and the first number is what you chose, and the last digit(s) are your age!

poemon1 · 2012-03-25 14:26:48

scimonster wrote:
poemon1 wrote:
werdna123 wrote:
I found that pretty easy.
I know. Lol. Can you do this: y=x^x/(7^4/7)
x=2???
y=0.01166

i didnt get that. Did you press = twice? i got 343.

slinger · 2012-03-25 14:27:12

That's what I got tongue

poemon1 · 2012-03-25 14:30:02

scimonster wrote:
poemon1 wrote:
werdna123 wrote:
I found that pretty easy.
I know. Lol. Can you do this: y=x^x/(7^4/7)
x=2???
y=0.01166

Oh yeah. XD i forgot a step tongue

Wickimen · 2012-03-25 14:30:39

Omg ok so I got one I want to share all across the innernets
x + x = x(2)
WHOA

LiFaytheGoblin · 2012-03-25 14:31:00

y=x^x/(7^4/7)
x=2

y = 2^2/(7^4/7)
y= 4/343

this took a long time to do ...

Last edited by LiFaytheGoblin (2012-03-25 14:31:54)

poemon1 · 2012-03-25 14:31:35

Wickimen wrote:
Omg ok so I got one I want to share all across the innernets
x + x = x(2)
WHOA

O_O wow. LOL

poemon1 · 2012-03-25 14:32:36

LiFaytheGoblin wrote:
y=x^x/(7^4/7)
x=2

y = 2^2/(7^4/7)
y= 4/343

I think I've done something wrong...^^

No, you did it rite smile . y=0.01166

poemon1 · 2012-03-25 14:35:01

poemon1 wrote:
LiFaytheGoblin wrote:
y=x^x/(7^4/7)
x=2

y = 2^2/(7^4/7)
y= 4/343

I think I've done something wrong...^^
No, you did it rite . y=0.01166

or, 0.011661807580174927113702623906706

poemon1 · 2012-03-25 14:36:31

ok, i got a harder one: what is the hypotenuse when a=12 and b=7?

AtomicBawm3 · 2012-03-25 14:38:27

Actually your first equation is wrong. PEMDAS states you should have done the exponent first, not multiply by 2. So instead you would get 2*2^4=2^5=32.

LiFaytheGoblin · 2012-03-25 14:41:48

( (2 * 3 + 5) * 50 + 1761) - 19YZ
= 550 + 1761 - 19YZ
= 2311 - 19YZ

Oh waa! It worked!

Last edited by LiFaytheGoblin (2012-03-25 14:42:07)

poemon1 · 2012-03-25 14:42:18

AtomicBawm3 wrote:
Actually your first equation is wrong. PEMDAS states you should have done the exponent first, not multiply by 2. So instead you would get 2*2^4=2^5=32.

oh, yeah. i always forget that. Thanks for reminding me smile

poemon1 · 2012-03-25 14:43:34

LiFaytheGoblin wrote:
( (2 * 3 + 5) * 50 + 1761) - 19YZ
= 550 + 1761 - 19YZ
= 2311 - 19YZ

Oh waa! It worked!

Ya. I tested it myself smile i got 712. im 12.

LiFaytheGoblin · 2012-03-25 14:44:39

.. phythagoras:
c² = a² + b²
a=12 and b=7
c² = 193
c ~ something between 13.5 and 14

Last edited by LiFaytheGoblin (2012-03-25 14:46:35)

poemon1 · 2012-03-25 14:47:51

LiFaytheGoblin wrote:
.. phythagoras:
c² = a² + b²
a=12 and b=7
c = 193² ~ something between 13.5 and 14

actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.

poemon1 · 2012-03-25 14:49:03

poemon1 wrote:
LiFaytheGoblin wrote:
.. phythagoras:
c² = a² + b²
a=12 and b=7
c = 193² ~ something between 13.5 and 14
actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.

how do you do the squared symbol?

scimonster · 2012-03-25 14:56:30

poemon1 wrote:
poemon1 wrote:
LiFaytheGoblin wrote:
.. phythagoras:
c² = a² + b²
a=12 and b=7
c = 193² ~ something between 13.5 and 14
actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.
how do you do the squared symbol?

Copy and paste.
I think LiFay is actually correct. Your answer is rather impossible, because the hypotenuse is the longest side.

LiFaytheGoblin · 2012-03-25 14:56:32

poemon1 wrote:
LiFaytheGoblin wrote:
.. phythagoras:
c² = a² + b²
a=12 and b=7
c = 193² ~ something between 13.5 and 14
actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.

why do you do (193- 12)-(193-7) = 5 ?
this would be (a²+b² - a) - (a² + b² - b)
I thought you would calculate it with this phythagoras thing a²+b²=c²? but maybe I understood it wrong, english math is new for me big_smile

EDIT: oh, I just saw what scimonsters wrote...

Last edited by LiFaytheGoblin (2012-03-25 14:57:30)

poemon1 · 2012-03-25 14:59:25

LiFaytheGoblin wrote:
poemon1 wrote:
LiFaytheGoblin wrote:
.. phythagoras:
c² = a² + b²
a=12 and b=7
c = 193² ~ something between 13.5 and 14
actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.
why do you do (193- 12)-(193-7) = 5 ?
this would be (a²+b² - a) - (a² + b² - b)
I thought you would calculate it with this phythagoras thing a²+b²=c²? but maybe I understood it wrong, english math is new for me

EDIT: oh, I just saw what scimonsters wrote...

Idk. It's just what I learned in my 6th grade year.

scimonster · 2012-03-25 15:06:24

poemon1 wrote:
LiFaytheGoblin wrote:
poemon1 wrote:

actually, it's: 2.2360679774997896964091736687313. 12^2 + 7^2=144+49=193
(193- 12)-(193-7) = 5 and do sqrt(5) = 2.2360679774997896964091736687313.
why do you do (193- 12)-(193-7) = 5 ?
this would be (a²+b² - a) - (a² + b² - b)
I thought you would calculate it with this phythagoras thing a²+b²=c²? but maybe I understood it wrong, english math is new for me

EDIT: oh, I just saw what scimonsters wrote...
Idk. It's just what I learned in my 6th grade year.

I'm in 8th grade, and learned the Pythagorean theorem straight from Khan Academy.

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#1 2012-03-25 14:18:35

mathematical equations

Code:

#2 2012-03-25 14:19:55

Re: mathematical equations

#3 2012-03-25 14:22:48

Re: mathematical equations

werdna123 wrote:

#4 2012-03-25 14:25:42

Re: mathematical equations

poemon1 wrote:

werdna123 wrote:

#5 2012-03-25 14:25:45

Re: mathematical equations

#6 2012-03-25 14:26:48

Re: mathematical equations

scimonster wrote:

poemon1 wrote:

werdna123 wrote:

#7 2012-03-25 14:27:12

Re: mathematical equations

#8 2012-03-25 14:30:02

Re: mathematical equations

scimonster wrote:

poemon1 wrote:

werdna123 wrote:

#9 2012-03-25 14:30:39

Re: mathematical equations

#10 2012-03-25 14:31:00

Re: mathematical equations

#11 2012-03-25 14:31:35

Re: mathematical equations

Wickimen wrote:

#12 2012-03-25 14:32:36

Re: mathematical equations

LiFaytheGoblin wrote:

#13 2012-03-25 14:35:01

Re: mathematical equations

poemon1 wrote:

LiFaytheGoblin wrote:

#14 2012-03-25 14:36:31

Re: mathematical equations

#15 2012-03-25 14:38:27

Re: mathematical equations

#16 2012-03-25 14:41:48

Re: mathematical equations

#17 2012-03-25 14:42:18

Re: mathematical equations

AtomicBawm3 wrote:

#18 2012-03-25 14:43:34

Re: mathematical equations

LiFaytheGoblin wrote:

#19 2012-03-25 14:44:39

Re: mathematical equations

#20 2012-03-25 14:47:51

Re: mathematical equations

LiFaytheGoblin wrote:

#21 2012-03-25 14:49:03

Re: mathematical equations

poemon1 wrote:

LiFaytheGoblin wrote:

#22 2012-03-25 14:56:30

Re: mathematical equations

poemon1 wrote:

poemon1 wrote:

LiFaytheGoblin wrote:

#23 2012-03-25 14:56:32

Re: mathematical equations

poemon1 wrote:

LiFaytheGoblin wrote:

#24 2012-03-25 14:59:25

Re: mathematical equations

LiFaytheGoblin wrote:

poemon1 wrote:

LiFaytheGoblin wrote:

#25 2012-03-25 15:06:24

Re: mathematical equations

poemon1 wrote: