Scratch

Hello Again,
I edited my program and it still doesn't work help.

import  java.util.Scanner;

class apples{
    public static void main(String args[]) {
        Scanner x = new Scanner(System.in);
       
        int num = 6;
       
        System.out.println("Try to Guess What Number I am.");
        switch (x){
        case (x == num): 
            System.out.println("Congradulations, you guessed it.")
            brake;
        case (x <= num):    
        System.out.println("Your Wrong Try Again. The Number is < the number you guessed.");
        case (x >= num):
            System.out.println("Your Wrong Try Again. The Number is > the number you guessed.");
        }
    }
}

I finally understand that I can't do this with the scanner, but is there another way to do this? Please Help. Thanks!

x itself isn't an integer value - it's a reference to the object of the Scanner class that you created. So naturally, you can't check its value against that of an integer, because it doesn't have a numerical value in that sense.

Instead, what you want is a method from the Scanner class that takes the next parseable integer - that is, the next integer entered by the user that it can find. What you want to do is to create a variable of type int and make it equal to "x.nextInt()", then check that against the num variable.

I hope that makes sense. I'm not terribly good at explaining things. :S

16Skittles wrote:

Try heading over to the official topic. However, since I am the owner of the official topic, I'll try to help you here. Actually, Harakou is right, and he already answered it. I went through a whole long thing about this about how to get a string, then realizing that it was completely unnecessary XD

http://scratch.mit.edu/forums/viewtopic.php?id=88581