Scratch

Happy Birthday! 

Happy Birthday!

Take your time 

Can I be an advertiser?

I'm very skilled at BBCode and I'd like to take the chance to be part of a group which (might be) quite sucsessful. So can I?

Hardmath123 wrote:

amcerbu: Once sci's done, add something to test for mismatched brackets and when you have something like 5√2 or (1)(2) replace them with 5*√2 or (1)*(2)

Okay, here's what I'm gonna do:

Complete the setup engine, which will "tokenize" the input into a list.  There are some revisions I would like to make to Scimonster's engine (sorry). 

Insert * for implied multiplication. 

Locate pairs of corresponding parentheses, and store their locations (token #'s) to two separate lists.  This will be necessary to check for mismatched brackets and syntax errors. 

Am I doing someone else's job?

EDIT: By the way, this is how the parentheses locations will work: one temporary variable will increase from 0 until it reaches "(", and another variable will start at that location, and increase until it reaches ")" (and has passed an equal number of "(" and ")" already- we don't want it picking up the first one it stumbles across).  That means that innermost brackets will appear at the end of the parentheses location lists, and in order from left to right.  So...

a+(b(c+d))
1234567890
will report as
( list- 3 5 
) list- 0 9

Note- I used 0 instead of 10, didn't want to run out of digits. 

Notice that the innermost brackets - at locations 5 and 9 - are the last members of their respective lists.

Last edited by amcerbu (2011-05-01 21:50:38)

@Hardmath123- Sorry to be picky, but you spelled my username wrong under the People who want to make a company heading.  I just don't want the name written wrong in project notes and things like that.  Thanks.

EDIT: I am now advertising.

Last edited by amcerbu (2011-05-02 02:06:50)

scimonster wrote:

amcerbu wrote:

sinh(x)- 0.5(e^x - e^-x)
cosh(x)- 0.5(e^x + e^-x)
tanh(x)- sinh(x)/cosh(x)

asinh(x)- ln (x + sqrt(x^2 + 1) )
acosh(x)- ln (x + sqrt(x^2 - 1) )
atanh(x)- 0.5(ln ( (1+x) / (1-x) ) )

I really don't think we need to include them, though.

Yeah... 

amcerbu wrote:

"sinh" is 'sin hyperbolic".  Darthpickley suggested that we include the hyperbolic functions.  Here's the Wikipedia article.

EDIT: Time to get started on my job.

I don't think we need them either if you just posted workarounds.

I only suggested it because it is really useful for people who live on hyperbolic planes...
wait, that's not really anybody...
well, I still just feel like it isn't the most difficult thing to add in to anything.

Hardmath123 wrote:

amcerbu wrote:

Locate pairs of corresponding parentheses, and store their locations (token #'s) to two separate lists.  This will be necessary to check for mismatched brackets and syntax errors. 

Am I doing someone else's job?

EDIT: By the way, this is how the parentheses locations will work: one temporary variable will increase from 0 until it reaches "(", and another variable will start at that location, and increase until it reaches ")" (and has passed an equal number of "(" and ")" already- we don't want it picking up the first one it stumbles across).  That means that innermost brackets will appear at the end of the parentheses location lists, and in order from left to right.  So...

Code:

a+(b(c+d))
1234567890
will report as
( list- 3 5 
) list- 0 9

Note- I used 0 instead of 10, didn't want to run out of digits. 

Notice that the innermost brackets - at locations 5 and 9 - are the last members of their respective lists.

NO!!!
It just needs to set a variable to
2+3
if the setup list is:
(
5
+
(
2
+
3
)
+
2
)

THAT's ALL

Wait.
Isn't that hpotter's job?

amcerbu wrote:

Hardmath123 wrote:

NO!!!
It just needs to set a variable to
2+3
if the setup list is:
(
5
+
(
2
+
3
)
+
2
)

THAT's ALL

But how does it know that 2+3 are inside the parentheses?  Could I have some pseudocode?

You said I should make something that checks for misplaced brackets?  How will that work in the system you described?

You just make sure the number of "("s is the same as the number of ")"s. 

Perhaps like this:

delete (all) of [temps]
add (0) to [temps]
add (0) to [temps]
add (0) to [temps]
repeat (length of [Engine])
  replace item (1) of [temps] with ((item (1) of [temps]) + (1))
  if <(item (item (1) of [temps]) of [Engine]) = "(">
    replace item (2) of [temps] with ((item (2) of [temps]) + (1))
  if <(item (item (1) of [temps]) of [Engine]) = ")">
    replace item (3) of [temps] with ((item (3) of [temps]) + (1))

Item 2 is (s and item 3 is )s.

EDIT: Why don't I just do it, now that I told you the code? 

Last edited by scimonster (2011-05-02 09:00:30)

amcerbu wrote:

Sorry to make you do it... I wasn't sure what Hardmath123 was asking for.

It's fine, just took a minute. 

I'm thinking that if we're going to stay together, a graphing calculator would be a great thing to make using Xenon.

amcerbu wrote:

applejack wrote:

I'm thinking that if we're going to stay together, a graphing calculator would be a great thing to make using Xenon.

+1

That would be cool. 

Support, something like that.  It's kinda for voting.

We're still working on Xenon, and if we did a graphing calculator afterword, you'd just put in the the part that y (or f(x)) was equal to. it would just substitute x for a different number each time.

bbbeb wrote:

1. I'm back here!
2. I would love to eat lots of watermelon until I explode or turn into an epic kirby.
3. A graphing calculator? IS THIS SRS BIZNESS? if so, its going to be a problem...

(We'd need like y=mx+b, ax+bx=c, x^2+ax+b= 0; )
That would be an issue for my etreme hatred of fluffy white dogs.