Scratch

so like "delete item of list that = "rabbit"" ? There's no fast way using original Scratch, but you use a counting variable and a repeat script.

[set [var1] to (0)]
|repeat (length of [list]]
|[change [var1] by (1)]
||if <(item (var1) of [list]) = [rabbit]>
||[delete item (var1) of [list]
||[stop script]
||endIf
||endRepeat

Hope that's clear! If you wanted to achive this using the modification Panther then you could use the  (place of [ ] in [list]) block from the Block Library.