No, but you can do it this way:
if (X/F) = round(X/F)
then whole number
else not whole number
You can see that type of stuff in these projects:
http://scratch.mit.edu/projects/BoltBait/515051
http://scratch.mit.edu/projects/BoltBait/516292
Last edited by BoltBait (2009-06-30 04:49:05)
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